In an automobile collision, a 44-kilogram passenger moving at 15 meters per second is brought to rest by an air bag during a 0.10-second time interval. What is the magnitude of the average force exerted on the passenger during this time?

6,600N

Explanation:

According to second law of motion, Force = mass * acceleration

If acceleration = change in velocity/time = 15/0.10

Acceleration = 150m/s²

Given mass = 44kg

Force = 44 * 150

Force = 6,600N

Magnitude of the average force exerted on the passenger during this time is 6,600N