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26 December, 18:18

An initially uncharged 3.53 * 10 - 6 F capacitor and a 7290 Ω resistor are connected in series to a 1.50 V battery that has negligible internal resistance. What is the initial current I 0 in the circuit?

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  1. 26 December, 18:26
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    The initial current, Io = 2.06*10^-4A

    Explanation:

    The I itial current, Io of a circuit is given by:

    Io = Vo/R

    Where Vo = initial votage

    R = resistance in ohms

    Given:

    Vo = 1.50V

    R = 7290ohms

    Io = 1.50 / 7290

    Io = 2.06 * 10^-4A
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