In the formation of the compound of sodium chloride A a chloride ion donates two protons to a sodium ion. B a chlorine atom donates an electron to a sodium atom. C a sodium atom donates an electron to a chlorine atom. D the sodium and chlorine atoms share a pair of electrons equally.

Question

Alfie

Physics

21 February, 22:22

In the formation of the compound of sodium chloride A a chloride ion donates two protons to a sodium ion. B a chlorine atom donates an electron to a sodium atom. C a sodium atom donates an electron to a chlorine atom. D the sodium and chlorine atoms share a pair of electrons equally.

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Aaliyah Key · Answer 1

Answer : The correct option is, (C) a sodium atom donates an electron to a chlorine atom.

Explanation:

Covalent compound : It is defined as the compound which is formed by the sharing of electrons between the atoms forming a compound.

The covalent compound are usually formed when two non-metals react.

Ionic compound : It is defined as the compound which is formed when electron gets transferred from one atom to another atom.

Ionic compound are usually formed when a metal reacts with a non-metal.

As we know that the sodium is an alkali metal and has one valence electron and chlorine is a non-metal and has 7 valence electrons.

When sodium atom donates an electron to a chlorine atom then it forms an ionic compound that is sodium chloride (NaCl).

Hence, the correct option is, (C) a sodium atom donates an electron to a chlorine atom.