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9 February, 22:59

An ice cube (n = 1.31) has a layer of water (n = 1.33) on it. What is the critical angle for a ray in water trying to enter the ice?

(Unit=deg)

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  1. 9 February, 23:15
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    Given that,

    The Refractive index of glass is

    n (ice) = 1.31

    The refractive index of water is

    n (water) = 1.33

    What is the critical angle?

    From water to ice

    Critical angle is given as.

    Using Snell's Rule.

    Sin (θc) = n1 / n2

    for total internal reflection the incident ray is always in the denser medium! So, water is the more denser than ice.

    Then,.

    Sin (θc) = n (ice) / n (water)

    Sin (θc) = 1.31 / 1.33

    Sin (θc) = 0.98496

    θc = arcSin (0.98496)

    θc = 80.05°

    The critical angle is 80.05°
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