The coefficient of kinetic friction between a suitcase and the floor is 2.76. if the suitcase has a mass of 71.5 kg, how far can it be pushed across the level floor with 670 j of work?

suitcase can be pushed to a distance of 0.35 m

Explanation:

Work done = Ff d

w = 670 J

Ff = force of friction

d = distance

force of friction is given by Ff=μ mg

μ = coefficient of friction=2.76

m=mass=71.5 kg

so Ff = (2.76) (71.5) (9.8)

Ff=1934 N

so W = Ff d

670 = 1934 d

d=0.35 m