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16 September, 18:42

If a rock climber accidentally drops a 52.5-g piton from a height of 325 meters, what would its speed be just before striking the ground? ignore the effects of air resistance.

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  1. 16 September, 19:11
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    Ignoring air resistance, the Kinetic energy before hitting the ground will be equal to the potential energy of the Piton at the top of the rock.

    So we have 1/2 MV^2 = MGH

    V^2 = 2GH

    V = âš2GH

    V = âš (2 * 9.8 * 325)

    V = âš 6370

    V = 79.81 m/s
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