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29 October, 23:55

When two resistors are connected in parallel across a battery of unknown voltage, one resistor carries a current of 3.3 a while the second carries a current of 1.8

a?

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  1. 30 October, 00:19
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    Correct question: When two resistors are connected in parallel across a battery of unknown voltage, one resistor carries a current of 3.3 A while the second carries a current of 1.8 A.

    What current will be supplied by the same battery if these two resistors are connected to it in series?

    Answer:

    1.164 A

    Explanation:

    From the question,

    Let the unknown voltage of the batter = V.

    Since the two resistors are connected in parallel,

    The voltage across each of the resistor is the same = V,

    Then,

    From ohm's law,

    V = IR ... Equation 1

    Where V = Voltage, I = Current, R = Resistance.

    make R the subject of the equation

    R = V/I ... Equation 2

    For the first resistor,

    Given: I₁ = 3.3 A, V = V.

    Substitute into equation 2

    R₁ = V/3.3 Ω

    For the second resistor,

    Given: I₂ = 1.8 A

    Substitute into equation 2

    R₂ = V/1.8 Ω.

    When the Resistors are connected in series,

    Rt = R₁+R₂

    Where Rt = Total resistance.

    Rt = V/3.3+V/1.8

    Rt = (1.8V+3.3V) / (3.3*1.8)

    Rt = 5.1V/5.94

    Rt = 0.859V.

    Applying,

    I' = V/Rt

    where I' = current supplied by the battery, If the two resistors are connected in series

    I' = V/0.859V

    I' = 1.164 A
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