For the following question neglect air resistance. Pay particular attention to whether the answer involves "absolute" quantities that have only magnitude (e. g., speed) or quantities that can have either sign (e. g., velocity). Take upward to be the positive direction. If the ball that is thrown downward has an acceleration of magnitude a a at the instant of its release (i. e., when there is no longer any force on the ball due to the woman's hand), what is the relationship between a a and g g, the magnitude of the acceleration of gravity? If the ball that is thrown downward has an acceleration of magnitude / texttip{a}{a}a at the instant of its release (i. e., when there is no longer any force on the ball due to the woman's hand), what is the relationship between / texttip{a}{a}a and / texttip{g}{g}g, the magnitude of the acceleration of gravity?

Question

Ryleigh Rodgers

Physics

18 May, 10:57

For the following question neglect air resistance. Pay particular attention to whether the answer involves "absolute" quantities that have only magnitude (e. g., speed) or quantities that can have either sign (e. g., velocity). Take upward to be the positive direction. If the ball that is thrown downward has an acceleration of magnitude a a at the instant of its release (i. e., when there is no longer any force on the ball due to the woman's hand), what is the relationship between a a and g g, the magnitude of the acceleration of gravity? If the ball that is thrown downward has an acceleration of magnitude / texttip{a}{a}a at the instant of its release (i. e., when there is no longer any force on the ball due to the woman's hand), what is the relationship between / texttip{a}{a}a and / texttip{g}{g}g, the magnitude of the acceleration of gravity?

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Tiggy · Answer 1

Answer:a=g

Explanation: when the ball is thrown downwards gravity is acting on the ball, there is no force opposing gravity therefore it's acceleration will be due to gravity acting on it that is why a=g