Josh rolled a bowling ball down a lane in 2.5 seconds. The ball travelled at a constant acceleration of 1.8 m/s/s down the lane and was traveling at a speed of 7.6 m/s by the time it reached the pins at the end of the lane. How fast was the ball going when it left Josh's hand?

Question

Adalynn Singleton

Physics

19 April, 08:03

Josh rolled a bowling ball down a lane in 2.5 seconds. The ball travelled at a constant acceleration of 1.8 m/s/s down the lane and was traveling at a speed of 7.6 m/s by the time it reached the pins at the end of the lane. How fast was the ball going when it left Josh's hand?

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Answers (1)

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Kylie Underwood · Answer 1

Ok, so slope of the lane gives the ball a constant acceleration of 1.8 m/s for 2.5 s

[lane slope = arcsine (1.8/9.8) = 10.6°]

which increases speed of the ball by

1.8 (2.5) = 4.5 m/s

The ball reaches the pins with a speed = 7.6 m/s, so it must have left Josh's hand with a speed of

7.6 - 4.5 = 3.1 m/s ANS