After a golf ball is hit it takes off with an initial speed of 29.5 m/s and at an angle of 34.5° with respect to the horizontal. The golf field is flat and horizontal. Neglecting air resistance how far will the golf ball fly? Submit Answer Tries 0/12 How high will the golf ball rise? Submit Answer Tries 0/12 How much time will the ball spend in the air? Submit Answer Tries 0/12 How far would the ball fly if the initial speed was doubled? Submit Answer Tries 0/12 How much time would the ball spend in the air in this second case?

Question

Drake Hernandez

Physics

27 August, 09:15

After a golf ball is hit it takes off with an initial speed of 29.5 m/s and at an angle of 34.5° with respect to the horizontal. The golf field is flat and horizontal. Neglecting air resistance how far will the golf ball fly? Submit Answer Tries 0/12 How high will the golf ball rise? Submit Answer Tries 0/12 How much time will the ball spend in the air? Submit Answer Tries 0/12 How far would the ball fly if the initial speed was doubled? Submit Answer Tries 0/12 How much time would the ball spend in the air in this second case?

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Answers (1)

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Leroy Hayes · Answer 1

The golf ball will bounce at angle of 34.5 ° with speed of 29.5 m/s.

Range R = u²sin2θ / g

= 29.5² sin 2 x 34.5 / g

= 29.5² sin 69 / g

= 82.9 m

maximum height

= u²sin²34.5 / 2g

= 29.5² sin² 34.5 / 2x 9.8

= 14.24 m

Time of flight

= 2 usin 34.5 / g

= 2 x 29.5 x sin 34.5 / g

= 3.4 s

Range ∝ u²

new Range after doubling u = 4 x 82.9

= 331.6 m

Time of flight ∝ u

new time of flight after doubling u

= 2 x 3.4

= 6.8 s