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25 April, 04:12

Two light bulbs each having a resistance of 3ohms are connected in series to a battery marked 12 volts. how much current will flow in the circuit

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  1. 25 April, 04:30
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    Givens

    Total Resistance (the bulbs are connected in series)

    R = r1 + r2 r1 = 3 ohms r2 = 3 ohms R = 3 + 3 = 6 ohms E = 12 volts I = ?

    Formula

    E = I * R

    Solution

    12 = I * 6 Divide both sides by 6

    12/6 = I*6/6

    2 = I

    The current = 2 amperes. Answer
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