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27 May, 14:55

Calculate the conductance of a conduit the cross-sectional area of which is 3.0 cm2 and the length of which is 9.0 cm, given that its conductivity is 0.80 ohm-1cm-1.

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  1. 27 May, 15:02
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    For resistance we have R=ρ l/a

    thus for conductance we have K=σ a/l

    conductance, K=1/R

    conductivity,σ = 1/ρ

    σ =.80 Ω-1 cm-1

    l = 9 cm

    a = 3 cm²

    K=.80 * 3/9

    =0.26 Ω-1
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