Show that the difference in volume across a first-order phase boundary is given

by ∆V = - ∆F/P.

Question

Karley Cisneros

Physics

7 November, 04:46

Show that the difference in volume across a first-order phase boundary is given

by ∆V = - ∆F/P.

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Sage Odonnell · Answer 1

G as a function of P at constant T for liquid and solid phases. As we can see from the fundamental equation, dG = VdP - SdT, the free energy of a phase increases with pressure: If the two phases have different molar volumes

Show that the difference in volume across a first-order phase boundary is givenby ∆V = - ∆F/P.

Show that the difference in volume across a first-order phase boundary is given

by ∆V = - ∆F/P.