Ask Question
7 May, 01:59

There are two tuning forks struck at the same time. One tuning fork is tuned to a frequency note of 500 Hz. The other is tuned to a frequency of 487 Hz. How many beats will occur in 2 seconds?

+1
Answers (1)
  1. 7 May, 02:28
    0
    Answer: 26 beats in 2 seconds

    Explanation:

    The number of beats per second = frequency of tuning fork 1 - frequency of tuning fork 2.

    Given:

    - frequency of tuning fork 1 = 500Hz

    - frequency of tuning fork 2 = 487Hz

    Thus,

    Beats per second = 500 - 487

    = 13 beats per second

    Therefore in two (2) seconds, you will have 2 x 13 = 26 seconds.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “There are two tuning forks struck at the same time. One tuning fork is tuned to a frequency note of 500 Hz. The other is tuned to a ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers