At amusement parks, there is a popular ride where the floor of a rotating cylindrical room falls away, leaving the backs of the riders "plastered" against the wall. Suppose the radius of the room is 2.0 m, the mass of the person is 50 kg and the speed of the wall is 10.0 m/s when the floor falls away. (Note that in a sense this is similar to the demonstration that you saw in class with sponge in a barrel). What is the radius of the chamber?

Question

Addisyn Ponce

Physics

26 May, 00:18

At amusement parks, there is a popular ride where the floor of a rotating cylindrical room falls away, leaving the backs of the riders "plastered" against the wall. Suppose the radius of the room is 2.0 m, the mass of the person is 50 kg and the speed of the wall is 10.0 m/s when the floor falls away. (Note that in a sense this is similar to the demonstration that you saw in class with sponge in a barrel). What is the radius of the chamber?

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Wayne · Answer 1

Answer: radius of the chamber = 2.0m

Centripetal force acting on the person = 2500N

Explanation:

Radius of the chamber/room is given and its = 2.0m

Calculating centripetal force Fc,

Fc=MV2/r

Where M is mass of the person r = radius of the room

Fc = 50kg * 10 * 10/2m = 2500N

Goodluck ...