A passenger on a moving train walks at a speed of 1.40 m/s due north relative to the train. The train is traveling at 3.5 m/s due east relative to the ground. What are the magnitude and direction of the velocity of the passenger relative to the ground

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Physics

6 June, 18:41

A passenger on a moving train walks at a speed of 1.40 m/s due north relative to the train. The train is traveling at 3.5 m/s due east relative to the ground. What are the magnitude and direction of the velocity of the passenger relative to the ground

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Heath · Answer 1

v = 4.9 m/s in east direction (or v=4.9 m/s * i)

Explanation:

Since the passenger moves along the train (in the north direction relative to the train) then if the train is traveling east relative to the ground, the passenger will also travel to the east relative to the ground.

Then the magnitude of the velocity will be

v = 1.40 m/S + 3.5 m/s = 4.9 m/s

v = 4.9 m/s

and the direction will be east (if the x axis represents east direction and y-axis the north direction, then the velocity vector will be v=4.9 m/s * i)