Ask Question
29 April, 07:54

In 2007, Michael Carter (U. S.) set a world record in the shot put with a throw of 24.77 m. What was the initial speed of the shot if he released it at a height of 2.10 m and threw it at an angle of 38.0o above the horizontal

+4
Answers (1)
  1. 29 April, 08:07
    0
    The horizontal displacement of throw = 24.77 m

    vertical displacement of throw = 2.1 m

    Let u be the initial speed of throw.

    vertical component = u sin38

    =.6156 u

    horizontal component of speed of throw = u cos 38

    =.788 u

    Let t be time of flight.

    For horizontal displacement

    24.77 =.788 u t

    t = 24.77 /.788 u

    For vertical displacement : --

    s = ut + gt²

    2.1 = -.6156 u t + 4.9 t²

    = -.6156 u x (24.77 /.788 u) + 4.9 x t²

    2.1 = - 19.35 + 4.9 t²

    21.45 = 4.9 t²

    t = 2.1 s

    t = 24.77 /.788 u

    u = 24.77 /.788 t

    = 14.96 m / s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “In 2007, Michael Carter (U. S.) set a world record in the shot put with a throw of 24.77 m. What was the initial speed of the shot if he ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers