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30 April, 15:01

A gas is contained in a vertical, frictionless piston-cylinder device. The piston has a mass of 3.2 kg and a cross-sectional area of 35 cm2. A compressed spring above the piston exerts a force of 110 N on the piston. If the atmospheric pressure is 95 kPa, determine the pressure inside the cylinder.

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  1. 30 April, 15:26
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    146.826 KPa

    Explanation:

    Given:

    The mass of the piston = 3.2 kg

    Cross-sectional area = 35 cm²

    Force exerted by the spring = 110 N

    Atmospheric pressure = 95 KPa

    Now,

    the total pressure inside the cylinder is the sum of all the pressure exerted on it i, e the pressure due the weight of the piston, pressure due to the force by the spring and the atmospheric pressure.

    Now,

    the pressure due to the weight of the piston = Weight / Area

    = 3.2 * 9.81 / 0.0035

    = 31.392 / 0.0035

    = 8969 Pa

    = 8.969 KPa

    And,

    The pressure by the spring = 150 N / 0.0035

    or

    The pressure by the spring = 42,857 Pa = 42.857 KPa

    Thus,

    The total pressure

    95 + 8.969 + 42.857 = 146.826 KPa
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