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15 June, 19:00

In this problem, you will use your prior knowledge to derive one of the most important relationships in mechanics: the work-energy theorem. We will start with a special case: a particle of mass m moving in the x direction at constant acceleration a. During a certain interval of time, the particle accelerates from vi to vf, undergoing displacement s given by s=xf-xi.

Required:

a. Find the accerlation a of the particle

b. Find the force F acting on the particle

c. Find the net work W done on the particle by the external forces during the particle's motion.

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Answers (1)
  1. 15 June, 19:09
    0
    a)

    Work done by force = change in kinetic energy

    F x s = (vf² - vi²) / 2m

    F = (vf² - vi²) / 2ms

    acceleration = (vf² - vi²) / 2m²s

    b)

    F = (vf² - vi²) / 2ms [ calculated above ]

    c)

    Work done by force

    = change in kinetic energy

    = (vf² - vi²) / 2m
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