A rocket-launching vehicle is moving forward at a constant velocity of 5 m/s. a cannon on the vehicle shoots a shell straight up with a velocity of 20 m/s. the shell moves without friction, (no air resistance). how high does the shell go, in m?

Question

Maren Fitzgerald

Physics

3 July, 20:05

A rocket-launching vehicle is moving forward at a constant velocity of 5 m/s. a cannon on the vehicle shoots a shell straight up with a velocity of 20 m/s. the shell moves without friction, (no air resistance). how high does the shell go, in m?

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Chasity Marquez · Answer 1

For any object thrown upwards where only the force of gravity is acting upon it, uses the following formula for the maximum height attained.

H = v²/2g, where g = 9.81 m/s²

There are two information of velocities are given. However, we use the 20 m/s information because this is the launch velocity. Hence, the solution is as follows:

H = (20 m/s) ²/2 (9.81 m/s²)

H = 20.4 m