A 50 kg boy runs and jumps with a forward velocity of 1.5 m/s into a 125 kg stationary boat. What is the final velocity of the boy/boat system? 0.43 m/s, forward 0.43 m/s, backward 1.1 m/s, forward 1.1 m/s, backwar

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Physics

21 April, 16:56

A 50 kg boy runs and jumps with a forward velocity of 1.5 m/s into a 125 kg stationary boat. What is the final velocity of the boy/boat system? 0.43 m/s, forward 0.43 m/s, backward 1.1 m/s, forward 1.1 m/s, backwar

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Makayla Solis · Answer 1

The answer for the final velocity of the boy/boat system is 0.43 m/s forward. Given the following: I = m * V where I is the initial momentum of an object of mass m moving at a velocity V. Notice that momentum is a vector. Then, I = 50 kg * 1.5 m/s kg*m/sec. Use Vx = I / (M + m) in finding the final velocity. Therefore, Vx = 75 kg * m/sec (125 kg + 50 kg) = 0.43 m/sec approximately in forward direction.