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19 November, 07:45

Zach, whose mass is 80 kg, is in an elevator descending at

10 m/s. The elevator takes 3.0 s to brake to a stopat the first

floor.

a. What is Zach's apparent weight before theelevator starts

braking?

b. What is Zach's apparent weight while theelevator is braking?

+1
Answers (1)
  1. 19 November, 08:10
    0
    (a) apparent weight is actual weight = mg = (79) (9.81) = 775 N ANS (a) {reason: elevator is not accelerating therefore Z's net acceleration is "g"}

    (b) elevator decelerates at 12/2.5 = - 4.80 m/s this reduces net acceleration acting on Z to (9.81 - 4.80) = 5.01 m/s² while braking with 5.01 m/s² acting on Z, his apparent weight = (79) (5.01) = 396 N ANS (b)
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