A football quarterback runs 15.0 m straight down the playing field in 2.50 s. he is then hit and pushed 3.00 m straight backward in 1.75 s. he breaks the tackle and runs straight forward another 21.0 m in 5.20 s. calculate his average velocity (a) for each of the three intervals and (b) for the entire motion.

Question

Valentina Randall

Physics

23 September, 02:43

A football quarterback runs 15.0 m straight down the playing field in 2.50 s. he is then hit and pushed 3.00 m straight backward in 1.75 s. he breaks the tackle and runs straight forward another 21.0 m in 5.20 s. calculate his average velocity (a) for each of the three intervals and (b) for the entire motion.

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Harriet · Answer 1

Define

t = time (s),

dt = change in time (s)

d = distance (m).

The scenario is as follows:

t = 0 s: Begin. Quarterback runs forward.

d = 0

t = 2.5 s: Quarterback is tackled and pushed backward.

d = 15 m

t = 2.5+1.75 = 4.25 s: Quarterback resumes the run forward.

d = 15 - 3 = 12 m

t = 4.25+5.2 = 9.45 s: Quarerback runs another 21 m forward.

d = 12+21 = 33 m

The graph showing the scenario is shown below.

Calculations:

Interval 1:

Average velocty = 15/2.5 = 6.0 m/s

Interval 2:

Average velocity = (12 - 15) / (1.75) = - 1.7 m/s

Interval 3:

Average velocity = (33 - 12) / 5.2 = 4.0 m/s

Entire motion:

Average velocity = (33 - 0) / 9.45 = 3.5 m/s