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2 April, 17:04

A 20 kg child is on a swing that hangs from 3.0-m-long chains. what is her maximum speed if she swings out to a 45° angle?

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  1. 2 April, 17:29
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    The solution for this problem is:

    Remember that this doesn’t depend on the mass of the child.

    E = T + U = constant

    E (maximum height) = T + U = U = mgh = mg[r - r· cos (Θ) ]

    E (bottom height) = T + U = T = ½mv² = mg[r - r · cos (Θ) ]

    v² = 2g[r - r · cos (Θ) ]

    v = √ (2g[r-r·cos (Θ) ])

    = √ (2 (9.8) [3 - 3 · cos (45°) ])

    = 4.15 m/s or 15 kph
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