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2 November, 16:01

a driver travels 135 km, east in 1.5 h, stops for 45 minutes for lunch, and then resumes driving for the next 2.0 h through a displacement of 215 km, east. what is the driver's average velocity?

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  1. 2 November, 16:20
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    v = 98.75 km/h

    Explanation:

    Given,

    The distance driver travels towards the east, d₁ = 135 km

    The time period of the travel, t₁ = 1.5 h

    The halting time, tₓ = 46 minutes

    The distance driver travels towards the east, d₂ = 215 km

    The time period of the travel, t₁ = 2 h

    The average speed of the vehicle before stopping

    v₁ = d₁/t₁

    = 135/1.5

    = 90 km/h

    The average speed of vehicle after stopping

    v₂ = d₂/t₂

    = 215/2

    = 107.5 km/h

    The total average velocity of the driver

    v = (v₁ + v₂) / 2

    = (90 + 107.5) / 2

    = 98.75 km/h

    Hence, the average velocity of the driver, v = 98.75 km/h
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