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20 May, 21:54

An airplane flies eastward and always accelerates at a constant rate. at one position along its path it has a velocity of 26.3 m/s, it then flies a further distance of 48100 m and afterwards its velocity is 41.9 m/s. find the airplane/'s acceleration and calculate how much time elapses while the airplane covers those 48100 m.

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  1. 20 May, 22:13
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    We will use the formula / equation to determined the time.

    Distance = ½ * (vi + vf) * t

    48100 = ½ * (26.3 + 41.9) * t

    t = 48100 : 34.1 = 1410.557185 seconds

    We will use the formula / equation to determined the acceleration.

    vf = vi + a * t

    41.9 = 26.3 + a * 1410.557185

    a = (41.9 - 26.3) : 1410.557185 = 0.011059459 m/s^2

    We will use the formula / equation to determined the acceleration.

    vf^2 = vi^2 + 2 * a * d

    41.9^1 = 26.3^2 + 2 * a * 48100

    a = (41.9^2 - 26.3^2) : 96200 = 0. 011059459 m/s^2

    Since both answers are the same, I believe the acceleration is correct.
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