The force acting between two charged particles A and B is 5.2 x 105 newtons. Charges A and B are 2.4 x 102 meters apart. If the charge on particle A is 7.2 x 108 coulombs, what is the charge of particle B? (k 7 9.0 x 109 newton meters?/coulomb)

Question

Johnathon Mcpherson

Physics

12 August, 20:33

The force acting between two charged particles A and B is 5.2 x 105 newtons. Charges A and B are 2.4 x 102 meters apart. If the charge on particle A is 7.2 x 108 coulombs, what is the charge of particle B? (k 7 9.0 x 109 newton meters?/coulomb)

+4

Answers (1)

Know the Answer?

Chi Chi · Answer 1

In order to calculate the electric field strength, we may use the formula:E = kQ/d²Where Q is the charge and d is the distance between the charge and the test charge. Substituting the values into the equation:E = (9 x 10⁹) (8.7 x 10⁻⁹) / (3.5²) E = 6.39 Newtons per coulombTherefore, the answer is 6.4 Newtons/coulomb