You catch a volleyball (mass 0.270 kg) that is moving downward at 7.50 m/s. In stopping the ball, your hands and the volleyball descend together a distance of 0.150 m. How much work do your hands do on the volleyball in the process of stopping it?

Question

Maximilian Barton

Physics

23 November, 22:52

You catch a volleyball (mass 0.270 kg) that is moving downward at 7.50 m/s. In stopping the ball, your hands and the volleyball descend together a distance of 0.150 m. How much work do your hands do on the volleyball in the process of stopping it?

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Joshua Huffman · Answer 1

deceleration a

v² = u² - 2as

0 = 7.5² - 2 a x. 15

a = 187.5 m / s²

If R be the force exerted by hand

R - mg = ma

R = mg + ma

=.27 (9.8 + 187.5)

= 53.27 N

Work done by hand

= force x displacement

= 53.27 x -.15

= - 8 J