Standing on the surface of the Earth you drop a rock down a well and it falls for 5 seconds before hitting the bottom. How fast is it moving when it hits the bottom of the well

it was moving at 50m/s when it hits the well bottom

Explanation:

Using Newton first law of motion;

V=u+gt

v=final velocity (what we are about to calculate)

u=initial velocity which is 0

g = acceleration due to gravity 10m/s^2 (since its expressing free fall it will be positive)

t=time taken 5seconds

v=0+10 (5)

v=50m/s

49 m/s.

Explanation:

Given:

Time, t = 5 s

Vo = 0 m/s

a = 9.8 m/s2

Using equations of motion,

Vf = Vo + at

Vf = 0 + 9.8 * 5

= 49 m/s.