Ask Question
25 February, 14:04

An object with mass 60 kg moved in outer space. When it was at location its speed was 3.5 m/s. A single constant force N acted on the object while the object moved from location m to location m. Then a different single constant force N acted on the object while the object moved from location m to location m. What is the speed of the object at this final location?

final speed = m/s

+4
Answers (1)
  1. 25 February, 14:30
    0
    Sigma F. dS = total work done = change in kinetic energy

    (220, 320, - 120). (18-13,-11+19,-8+3) + (150, 230, 220). (22-18,-17+11,-3+8) = 1/2 * 60 * (V^2 - 3.5^2)

    220*5+320*8 + - 120*-5 + 150*4 + 230 * 6 + 220 * - 5 = ...

    simplify his
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “An object with mass 60 kg moved in outer space. When it was at location its speed was 3.5 m/s. A single constant force N acted on the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers