An object with mass 60 kg moved in outer space. When it was at location its speed was 3.5 m/s. A single constant force N acted on the object while the object moved from location m to location m. Then a different single constant force N acted on the object while the object moved from location m to location m. What is the speed of the object at this final location?

final speed = m/s

Question

Elise Tran

Physics

25 February, 14:04

An object with mass 60 kg moved in outer space. When it was at location its speed was 3.5 m/s. A single constant force N acted on the object while the object moved from location m to location m. Then a different single constant force N acted on the object while the object moved from location m to location m. What is the speed of the object at this final location?

final speed = m/s

+4

Answers (1)

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Renee Mcmillan · Answer 1

Sigma F. dS = total work done = change in kinetic energy

(220, 320, - 120). (18-13,-11+19,-8+3) + (150, 230, 220). (22-18,-17+11,-3+8) = 1/2 * 60 * (V^2 - 3.5^2)

220*5+320*8 + - 120*-5 + 150*4 + 230 * 6 + 220 * - 5 = ...

simplify his