The position of a 2.75*105n training helicopter under test is given by r⃗ = (0.020m/s3) t3i^ + (2.2m/s) tj^ - (0.060m/s2) t2k^. part a find the net force on the helicopter at t=5.0s.

Question

Ingrid Parsons

Physics

19 March, 19:39

The position of a 2.75*105n training helicopter under test is given by r⃗ = (0.020m/s3) t3i^ + (2.2m/s) tj^ - (0.060m/s2) t2k^. part a find the net force on the helicopter at t=5.0s.

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Craig Huber · Answer 1

F (t) = 1.7⋅10^4i^-3.4⋅10^3k

Here we have the components in the x-direction and the y-direction

Fx = 17000 N

Fz = 3400 N

The resultant force is given by

F = sqrt (Fx2 + Fz2)

= sqrt (170002 + 34002)

= 17336.67 N

Net force on the helicopter at t = 5.0 s is 17336.67 N