Two ice skaters stand at rest in the center of an ice rink. when they push off against one another the 45-kg skater acquires a speed of 0.62 m/s. if the speed of the other skater is 0.89 m/s, what is this skater's mass?

Question

Esteban Fry

Physics

25 August, 09:15

Two ice skaters stand at rest in the center of an ice rink. when they push off against one another the 45-kg skater acquires a speed of 0.62 m/s. if the speed of the other skater is 0.89 m/s, what is this skater's mass?

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Answers (1)

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Sammy Terrell · Answer 1

Two in middle, so Newton's 2nd law. Equal and opposite force (both are moving). You have to assume no friction since it's an ice rink.

Skater 1: 45kg 0.66m/s

Skater 2: xkg 0.81ms/

Since force is equal, 45*0.66=x*0.81

Solve for x.

So the answer would be 36.7kg