Ask Question
6 November, 08:24

During takeoff, an airplane climbs with a speed of 130 m/s at an angle of 47 degrees above the horizontal. The speed and direction of the airplane constitute a vector quantity known as the velocity. The sun is shining directly overhead. How fast is the shadow of the plane moving along the ground? (That is, what is the magnitude of the horizontal component of the plane's velocity?)

+4
Answers (1)
  1. 6 November, 08:50
    0
    130cos (47deg) = 88.6598 m/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “During takeoff, an airplane climbs with a speed of 130 m/s at an angle of 47 degrees above the horizontal. The speed and direction of the ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers