Ask Question
6 February, 05:53

A (n) 0.49 kg softball is pitched at a speed of 13 m/s. The batter hits it back directly at the pitcher at a speed of 23 m/s. The bat acts on the ball for 0.014 s. What is the magnitude of the impulse imparted by the bat to the ball?

+5
Answers (1)
  1. 6 February, 06:06
    0
    Impulse = 4.9 kgm/s

    Explanation:

    Impulse is given by change of momentum.

    Mass of softball = 0.49 kg

    Initial velocity of softball = 13 m/s

    Initial momentum = 0.49 x 13 = 6.37 kgm/s

    Final velocity of softball = 23 m/s

    Final momentum = 0.49 x 23 = 11.27 kgm/s

    Change of momentum = Final momentum - Initial momentum

    Change of momentum = 11.27 - 6.37

    Change of momentum = 4.9 kgm/s

    Impulse = Change of momentum

    Impulse = 4.9 kgm/s
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “A (n) 0.49 kg softball is pitched at a speed of 13 m/s. The batter hits it back directly at the pitcher at a speed of 23 m/s. The bat acts ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers