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22 July, 21:31

What is the speed of a ball thrown from 1.2m above the ground if it travels 13.7m horizontally before hitting the ground

i need this done quick

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Answers (1)
  1. 22 July, 21:39
    0
    The trick is to find the time.

    If the ball did not travel horizontally at all and was just dropped, how long would it take to hit the ground?

    Givens

    vi = 0

    d = 1.2 m

    a = 9.8 m/s^2

    Formula

    d = vi * t + 1/2 * a ^ t^2

    Solution

    1.2 = 0*t + 1/2 9.8 * t^2

    1.2 = 4.9 t^2

    t^2 = 1.2 / 4.9

    t^2 = 0.245

    sqrt (t^2) = sqrt (.245)

    t = 0.4949 seconds

    Answer

    You are not very clear about which answer you want. There are two of them. One is going horizontally and the other is vertically.

    Vertical

    vf^2 = vi^2 + 2*a*d

    vi = 0

    a = 9.8

    t = 0.4949

    vf^2 = 0^2 + 2 * 9.8 * 1.2

    vf^2 = 23.52

    sqrt (vf^2) = sqrt (23.52)

    vf = 4.85 m/s

    Horizontal

    This is likely what you are looking for.

    There is 0 acceleration horizontally.

    d = 13.5 m

    t = 0.4949

    s = ?

    s = d/t

    s = 13.5/0.4949

    s = 27.28

    Note

    You should note a couple of things.

    The horizontal and vertical speeds are not the same. The time is used for both the horizontal and vertical speeds. The horizontal and vertical distances are quite different. Horizontal accelerations for these type of questions is generally 0.
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