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28 December, 16:47

A + 8 μC charge lies 4 m to the left of a - 10 μC charge. A - 12 μC charge lies 8 m to its right. What is the resultant force on the center charge?

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  1. 28 December, 16:54
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    both side charges will exert force on central charge towards left so the two forces add up. Thus resultant force on centre charge is

    F = 9*10^9 x 8*10^-6*10*10^-6/16

    +

    9 * 10^9 * 10*10^-6*12*10^-6/64

    = 9 * 10^9 * 10^ - 12/16 (80+30)

    =6.18 * 10^-2 N

    or

    = 0.06 N
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