A rectangular garden has a perimeter of 54 feet. it's length is 3 less than twice its width. write and solve an equation to solve for the gardens dimensions

2 (L+W) = 54

L=2W-3

Substitute L in the first equation:

2 ((2W-3) + W) = 54.

Divide by 2:

(2W-3) + W=27

Simplify by collecting like terms:

3W-3=27.

Add 3:

3W=30.

Divide by 3 to get that

W=10.

Substitute the L and W relations to get

L=2W-3

L=2*10-3

L=17.

The answers are length is 17 and width is 10.