A 2.00 C charge moves from a + 50.0 V equipotential line to a + 40.0 V equipotential line. What is the change in the electric potential energy of the charge field system?

Question

Rosa Nichols

Physics

7 November, 10:34

A 2.00 C charge moves from a + 50.0 V equipotential line to a + 40.0 V equipotential line. What is the change in the electric potential energy of the charge field system?

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Answers (2)

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Cade Ali · Answer 1

Potential on first line, V1 = 50 V

Potential on second line, V2 = 40 V

Charge, q = 2 C

Change in potential, ΔV = V1 - V2 = 50 - 40 = 10 V

Potential energy is given by

U = q x ΔV

U = 2 x 10

U = 20 J

Alina Howell · Answer 2

Change in electric potential energy

= charge x potential difference

= 2 x (50 - 40)

= 20 J

Potential will be decreased by this amount.