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11 August, 17:06

An archer wishes to shoot an arrow at a target at eye level a distance of 50.0m away. If the initial speed imparted to the arrow is 70.0m/s, what angle should the arrow make with the horizontal as it is being shot?

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  1. 11 August, 17:15
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    Given:

    Hmax (distance) = 50.0m

    v ₀ = 70.0m/s

    Required:

    what angle should the arrow make with the horizontal as it is being shot

    Solution:

    Hmax = v ₀²sin²θ / 2g

    sin²θ = 2gHmax / v₀²

    sin²θ = 2 (9.81 m/s²) (50m) / (70 m/s) ²

    sin²θ = 0.200

    θ = 26.56°
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