A car of weight 1.8 x 10^4 N is accelerated uniformly from rest by a force of 5.0 x 10^3 N east for 6s. Calculate the following for the car the displacement from its original position.

Displacement = 50.04 m

Explanation:

Given,

Weight of car, W = 1.8 * 10⁴ N

Initial Velocity, u = 0

Force, F = 5 * 10³ N (at the East direction)

Time, t = 6s

Let 'd' be the displacement in the position of car in 6 seconds.

Mass of car, m = Weight/Gravity

m = 1.8 * 10⁴ N / 10 m/s²

m = 1.8 * 10³ kg

Now,

Force of car = Mass of car * acceleration of car

So, Acceleration = Force/Mass

Acceleration = 5 * 10³ N/1.8 * 10³ kg

Acceleration = 2.78 m/s²

By using the formula of second equation of motion.

s = ut + 1/2 at²

where, u = 0

So,

s = 1/2 at²

s = 1/2 * 2.78 * 6²

s = 1/2 * 2.78 * 36

s = 50.04 m

Here, s is 'd'. 's' and 'd' both are displacement.

50.04 m

Explanation:

Weight of car = 1.8 x 10^4 N

u = 0

F = 5 x 10^3 N east

Let d be the displacement in the position of car in 6 s.

Mass of car, m = Weight / g = 1.8 x 10^4 / 10 = 1.8 x 10^3 kg

Force = mass of car x acceleration of car

a = F / m = 5 x 10^3 / (1.8 x 10^3) = 2.78 m/s^2

Use third equation of motion

s = u t + 1/2 a t^2

d = 0 + 1/2 x 2.78 x 6 x 6

d = 50.04 m