The concentration of carbon monoxide in an urban apartment is 48μg/m3. What mass of carbon monoxide in grams is present in a room measuring 10.6ft*14.8ft*20.5ft?

Answer;

= 5.45 * 10-3 g or 5.45 mg

Explanation;

1 meter = 3.048 feet

Volume = 10.6 * 14.8 * 20.5 ft³ * (1/3.048 ft/m³)

= 113.57 m³

Therefore; the mass of carbon monoxide;

= 113.57 m³ * 48 * 10^-6 g/m³

= 5.45 * 10^-3 g

= 5.45 mg