A 0.9 kg football is thrown with a velocity of 22.0 m/s to the right. A stationary receiver catches the ball and brings it to rest in 0.06 seconds. What is the force exerted on the receiver?

-330 N.

Explanation:

Force is defined as the mass and the acceleration of a body.

The formula of force is given as,

F = m (v-u) / t ... Equation 1.

Where m = mass of the football, u = initial velocity of the football, v = final velocity of the football, t = time.

Given: m = 0.9 kg, u = 22.0 m/s, v = 0 m/s (brought it to rest), t = 0.06 seconds.

Substitute into equation 1,

F = 0.9 (0-22) / 0.06

F = 0.9 (-22/0.06)

F = - 330 N.

F = - 330 N.

Note: The force is negative because it acts against the the receiver.