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10 June, 02:12

A driver wearing a seat beat decelerates at roughly the same rate as the car it self. Since many modern cars have a "crumble zone" built into the front of the car, let us assume that the car decelerates of a distance of 0.9 m. What is the net force acting on a 65 kg driver who is driving at 18 m/sec and comes to rest in this distance

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  1. 10 June, 02:29
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    11,700Newton

    Explanation:

    According to Newton's second law, Force = mass * acceleration

    Given mass = 65kg.

    Acceleration if the car can be gotten using one of the equation of motion as shown.

    v² = u²+2as

    v is the final velocity = 18m/s

    u is the initial velocity = 0m/s

    a is the acceleration

    s is the distance travelled = 0.9m

    On substitution;

    18² = 0²+2a (0.9)

    18² = 1.8a

    a = 324/1.8

    a = 180m/²

    Net force acting on the body = 65*180

    Net force acting on the body = 11,700Newton
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