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16 January, 15:04

A 66.5-kg hiker starts at an elevation of 1270 m and climbs to the top of a peak 2660 m high.

(a) What is the hiker? s change in potential energy?

(b) What is the minimum work required of the hiker?

(c) Can the actual work done be greater than this? Explain.

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  1. 16 January, 15:30
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    Answer

    given,

    mass of the hiker = 66.5 kg

    elevation of the hiker, h₁ = 1270 m

    elevation of top peak, h₂ = 2660 m

    a) Change in potential energy

    Δ PE = m g h₂ - m g h₁

    Δ PE = m g (h₂ - h₁)

    Δ PE = 66.5 x 9.8 x (2660 - 1270)

    Δ PE = 905863 J

    b) Minimum work require by the hiker will be equal to Δ PE = 905863 J

    c) yes, it can be more than this, if friction is present on the surface.
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