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11 August, 16:48

A bag is dropped from a hovering helicopter. When the bag has fallen 2 seconds,

a. What is the bag's velocity?

b. How far has the bag fallen?

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Answers (1)
  1. 11 August, 17:03
    0
    A) Vt = Vo - gt

    = 0 - 9.8. 2

    = - 19.6 m/sec (acting downward)

    b) ∆y = Vt^2 - Vo^2 / 2g

    = (-19.6) ^2 - 0 / 19.6 = 19.6 meters
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