You have a string with a mass of 0.0123 kg. 0.0123 kg. You stretch the string with a force of 8.37 N, 8.37 N, giving it a length of 1.81 m. 1.81 m. Then, you vibrate the string transversely at precisely the frequency that corresponds to its fourth normal mode; that is, at its fourth harmonic. What is the wavelength?4λ4 of the standing wave you create in the string? What is the frequency f4?

Question

Jacoby Gill

Physics

4 January, 01:20

You have a string with a mass of 0.0123 kg. 0.0123 kg. You stretch the string with a force of 8.37 N, 8.37 N, giving it a length of 1.81 m. 1.81 m. Then, you vibrate the string transversely at precisely the frequency that corresponds to its fourth normal mode; that is, at its fourth harmonic. What is the wavelength?4λ4 of the standing wave you create in the string? What is the frequency f4?

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Answers (1)

Know the Answer?

Derek Flowers · Answer 1

v = 35.09m/s

f = 38.77Hz

Explanation:

Length 'L' = 1.81 m

Now, First off the fourth harmonic of a string with two nodes is given by:

L=2λ

1.81=2λ

λ = 1.81/2 = >0.905 m

Wave speed on a strecthed string is:

v=√ (Ft / (m/l))

v = √ (8.37) / (0.0123/1.81)

v = 35.09m/s

Next is to determine frequency i, e

v=λf or f = v/λ

f = 35.09/0.905

f = 38.77Hz