A grinding wheel with a moment of inertia of 2 kg-m2 has a 2.50 N-m torque applied to it. What is its final kinetic energy 10 seconds after starting from rest?

312 J

237 J

156 J

106 J

First you do 2.5 n-m / 2 kg-m2

This equals 1.25 rad/s^2

Then multiply rad/s^2 by 10 because of the amount of seconds

This equals 12.5 rad/s^2

Then do this following equation : (1/2) Iwf^2

Do (0.5) 12.5 * 12.5 * 2

This equals 156.25 J (meaning that the answer is C: 156 J)