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20 February, 00:10

A tall, open container is full of glycerine. At what depth h below the surface of the glycerine is the pressure 2170 Pa greater than atmospheric pressure? The density of glycerine is 1.26 * 10 3 kg/m 3.

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  1. 20 February, 00:18
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    Answer: 0.176 m

    Explanation:

    Given

    Pressure of glycerine, p = 2170 Pa

    Density of glycerine, ρ = 1.26*10^3 kg/m³

    Depth, h = ?

    To solve, we use the formula of pressure

    P = ρgh

    Where

    ρ = density of glycerine

    P = pressure of glycerine

    g = acceleration due to gravity

    h = depth of glycerine

    2170 = 1.26*10^3 * 9.8 * h

    2170 = 12348 * h

    h = 2170 / 12348

    h = 0.176 m

    Therefore, the depth below the surface at which the pressure of glycerine is greater than the atmospheric pressure is 0.176 m
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