Ask Question
1 June, 16:04

José is pinned against the walls of the Rotor, a ride with a radius of 3.00 meters that spins so fast that the floor can be removed without the riders falling. When the ride accelerates to a speed of 17.0 m/s, his angular momentum is 3570 kg m2/s. What is his mass?

Remember to identify all data (givens and unknowns), list equations used, show all your work, and include units and the proper number of significant digits

+3
Answers (1)
  1. 1 June, 16:26
    0
    r = radius of the circle of the ride = 3.00 meters

    v = linear speed of the person during the ride = 17.0 m/s

    m = mass of the person in angular motion in the ride

    L = angular momentum of the person in the ride = 3570 kg m²/s

    Angular momentum is given as

    L = m v r

    inserting the values

    3570 kg m²/s = m (17 m/s) (3.00 m)

    m = 3570 kg m²/s / (51 m²/s)

    m = 7 kg

    hence the mass comes out to be 7 kg
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “José is pinned against the walls of the Rotor, a ride with a radius of 3.00 meters that spins so fast that the floor can be removed without ...” in 📗 Physics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers