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11 February, 00:48

A 10.1-g bullet is fired into a stationary block of wood having mass m = 5.03 kg. The bullet imbeds into the block. The speed of the bullet-plus-wood combination immediately after the collision is 0.593 m/s. What was the original speed of the bullet? (Express your answer with four significant figures.)

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  1. 11 February, 00:52
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    The original speed of the bullet was of V1 = 295.9187 m/s.

    Explanation:

    m1 = 10.1 g = 0.0101 kg

    m2 = 5.03 kg

    V2 = 0.593 m/s

    V1=?

    m1*V1 = (m2+m1) * V2

    V1 = [ (m2+m1) * V2] / m1

    V1 = 295.9187 m/s
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